The Motivation For Isaac Newton To Discover His Laws Of Motion Was To Explain The Properties Of Planetary (2024)

Answer:

Precisionisdeterminedby a statistical method called a standard deviation Todetermineif a value is precise find the average of your data, then subtract eachmeasurementfrom it

Answer:

The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

1/Rₚ = 1/100 + 1/400 + 1/200

Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown

1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

Invert

Rₚ = 400/7

Rₚ = 57.14 Ω

345k

Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)

9.

Answer:

The formula is dimensionally correct.

Explanation:

Given

[tex]s = ut + \frac{1}{2}at^2[/tex]

Required

Prove its correctness

Write out the dimension of each:

[tex]s = M^0LT^0[/tex] --- displacement

[tex]ut = M^0LT^{-1} * T[/tex] --- velocity * time

[tex]\frac{1}{2}at^2 = M^0LT^{-2} * T^2[/tex] --- acceleration * square of time

The expression becomes:

[tex]s = ut + \frac{1}{2}at^2[/tex]

[tex]M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2[/tex]

Apply law of indices

[tex]M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}[/tex]

[tex]M^0LT^0 = M^0LT^{0} + M^0LT^{0}[/tex]

[tex]M^0LT^0 = M^0LT^{0}[/tex]

Both sides of the equation are equal

Answer:

E = 3.049 N/C

Explanation:

Induced electric field = e/2 *(pi) *r

Induced electric field = e /(3.14 *19.5) - Eq (1)

e = (pi)r^2*B/t

= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1

= 1.867 V

Substituting this value in equation 1, we get –

E = 1.867 V/(3.14 *19.5/100)

E = 3.049 N/C

Earth's distance from the sun doesn't change enough to cause seasonal differences. Instead, our seasons change because Earth tilts on its axis.

hope it helps.

Answer:

4.9 m/s²

Explanation:

Let T be the tension in the string

If a is the linear acceleration in the direction of the 3M mass, the equation of motion on the 3M mass is

3Mg - T = 3Ma (1)

Since the mass M moves upwards, its equation of motion is

T - Mg = Ma (2)

From (2)

T = Ma + Mg

substituting T into (1), we have

3Mg - (Ma + Mg) = 3Ma

3Mg - Ma - Mg = 3Ma

collecting like terms, we have

3Mg - Mg = 3Ma + Ma

2Mg = 4Ma

dividing both sides by 4M, we have

2Mg/4M = 4Ma/4M

g/2 = a

a = g/2

Since g = 9.8 m/s²,

a = 9.8 m/s²/2

a = 4.9 m/s²

The linear acceleration 'a' of the masses M and 3M is; a = 4.9 m/s²

We are told that;

Mass of first block = M

Mass of second block = 3M

Let the tension in the strings be T.

Now for first block we can write;

T - Mg = Ma - - - (1)

For second block, we can write;

3Mg - T = 3Ma - - - (2)

Where a is linear acceleration of the masses.

Let us add eq 1 to eq 2 to get;

T - Mg + 3Mg - T = Ma + 3Ma

2Mg = 4Ma

M will cancel out to get;

2g = 4a

Using division property of equality by dividing both sides by 2 to get;

g = 2a

Thus;

a = g/2

Where g is acceleration due to gravity = 9.8 m/s²

Thus;

a = 9.8/2

a = 4.9 m/s²

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Answer:

Work done is 882000joule.

power is 29400watt.

Explanation:

given,

Mass(m)=500kg

Acceleration due to gravity(g)=9.8m/s²

Height(h)=6m

Time taken(t)=30s

Workdone=?

Power=?

now,

workdone=force*displaxement

= m*g*h

=500*9.8*6

=8,82,000joule

so, the work done by the man is 8,82,000joule.

then,

power=workdone/time taken

=8,82,000/30

=29,400watt

so, the required power to lift a load is 29,400watt.

Answer:

F = 520 N

Explanation:

For this exercise the rotational equilibrium equation should be used

Σ τ = 0

Let's set a reference system with the origin at the back of the refrigerator and the counterclockwise rotation as positive. On the x-axis it is horizontal directed outward, eg the horizontal y-axis directed to the side and the z-axis vertical

Torque is

τ = F x r

the bold indicate vectors, we analyze each force

the applied force is horizontal along the -x axis, the arm (perpendicular distance) is directed in the z axis,

The weight of the body is the vertical direction of the z-axis, so the arm is on the x-axis

-F z + W x = 0

F z = W x

F = [tex]\frac{x}{z}[/tex] W

The exercise indicates the point of application of the force z = 1.5 m and the weight is placed in the center of mass of the body x = 0.6 m, we are assuming that the force is applied in the wide center of the refrigerator

let's calculate

F = 1300 0.6 / 1.5

F = 520 N

Answer:

True

Explanation:

The given statement is true because the scale height of the atmosphere (H) is a vertical distance over which the pressure and density of an atmosphere decrease by a certain factor. The scale height of the atmosphere has a constant value of 8,000 m and it often refers to the height one must ascend to achieve a certain value of density or pressure.

Thus, the scale height of the atmosphere (H) is a variable that meteorologists often use to do conversions from altitude to pressure.

Answer:

1. Rₑq = 4 Ω

2. R₂ = 6 Ω

3. Vₜ = 12 V, V₁ = 12 V, V₂ = 12 V

4. Iₜ = 3 A, I₁ = 1 A, I₂ = 2 A

Explanation:

1. Determination of the equivalent resistance

Voltage (V) = 12 V

Current (I) = 3 A

Resistance (Rₑq) =?

V= IRₑq

12 = 3 × Rₑq

Divide both side by 3

Rₑq = 12 / 3

Rₑq = 4 Ω

Thus, the equivalent resistance (Rₑq) = 4 Ω

2. Determination of R₂.

Equivalent resistance (Rₑq) = 4 Ω

Resistance 1 (R₁) = 12 Ω

Resistance 2 (R₂)

Since the resistor are in parallel arrangement, the value of R₂ can be obtained as follow:

Rₑq = R₁ × R₂ / R₁ + R₂

4 = 12 × R₂ / 12 + R₂

Cross multiply

4(12 + R₂) = 12R₂

48 + 4R₂ = 12R₂

Collect like terms

48 = 12R₂ – 4R₂

48 = 8R₂

Divide both side by 8

R₂ = 48 / 8

R₂ = 6 Ω

3. Determination of the total voltage (Vₜ), V₁ and V₂.

From the question given above, the total voltage is 12 V

Since the resistors are arranged in parallel connection, the same voltage will go through them.

Thus,

Vₜ = V₁ = V₂ = 12 V

4. Determination of the total current (Iₜ), I₁ and I₂

From the question given above, the total current (Iₜ) is 3 A

Next, we shall determine I₁. Since the resistors are arranged in parallel connection, different current will pass through each resistor respective.

Vₜ = V₁ = 12 V

R₁ = 12 Ω

I₁ =?

V₁ = I₁R₁

12 = I₁ ×12

Divide both side by 12

I₁ = 12 / 12

I₁ = 1 A

Next, we shall determine I₂. This can be obtained as follow:

Iₜ = 3 A

I₁ = 1 A

I₂ =?

Iₜ = I₁ + I₂

3 = 1 + I₂

Collect like terms

I₂ = 3 – 1

I₂ = 2 A

Answer:

Resistance is proportional to length and inversely proportional to area.

L1 = 5 cm

L2 = 10 cm

L3 = 15 cm

A1 = k * (.50 cm)^2

A2 = k * (.25 cm)^2 = 1/4 A1

A3 = k * (.05 cm)^2= 1/100 A1

R1 = 1 * 1 = 1

R2 = 2 * 4 = 8 R1

R3 = 3 * 100 = 300 R1

R3 has greatest resistance

We have that for the Question " constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110." it can be said that

the final velocity vf is

[tex]vf=3.83m/s[/tex]

and the applied force Fnew is

[tex]F_{new}=3.43N[/tex]

From the question we are told

A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force F new would give the box the same final velocity?

Generally the equation for the Force is mathematically given as

F_p-\mu mg=ma

Therefore

11-0.110*7*9.8=7*a

a=0.49m/s^2

Using Newtons equation

v^2=u^2+2as

v^2=0+2*0.49*15

v=3.83m/s

Therefore

F=ma

F=0.49*7

F_{new}=3.43N

Therefore

the final velocity vf is

[tex]vf=3.83m/s[/tex]

and the applied force Fnew is

[tex]F_{new}=3.43N[/tex]

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Explanation:

When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.

Answer:

100 milliliters

Explanation:

Answer:

g = 1.19 m / s²

Explanation:

Let's solve this problem in parts.

Let's start by looking for the speed of the pulse in the wire, the wave speed is constant

v = l / t

let's calculate

v = 1.52 / 0.0833

v = 18.25 m / s

now we can use the relationship between velocity and material properties

v = [tex]\sqrt{\frac{T}{\mu } }[/tex]

T = v² μ

let's calculate

T = 18.25² 4.41 10-4

T = 1.4688 10-1 N

finally let's use the equilibrium condition

T - W = 0

W = T

m g = T

g = T / m

we calculate

g = 1.4688 10⁻¹ / 0.123

g = 1.19 m / s²

Answer:

Characteristics of Nanotechnology

Explanation:

Nanotechnology deals with putting things together atom by atom and with structures so small they are invisible to the naked eye. It provides the ability to create materials, devices and systems with fundamentally new functions and properties

Answer:

Speed = 575 m/s

Mechanical energy is conserved in electrostatic, magnetic and gravitational forces.

Explanation:

Given :

Potential difference, U = [tex]$-3.45 \times 10^{-3} \ V$[/tex]

Mass of the alpha particle, [tex]$m_{\alpha} = 6.68 \times 10^{-27} \ kg$[/tex]

Charge of the alpha particle is, [tex]$q_{\alpha} = 3.20 \times 10^{-19} \ C$[/tex]

So the potential difference for the alpha particle when it is accelerated through the potential difference is

[tex]$U=\Delta Vq_{\alpha}$[/tex]

And the kinetic energy gained by the alpha particle is

[tex]$K.E. =\frac{1}{2}m_{\alpha}v_{\alpha}^2 $[/tex]

From the law of conservation of energy, we get

[tex]$K.E. = U$[/tex]

[tex]$\frac{1}{2}m_{\alpha}v_{\alpha}^2 = \Delta V q_{\alpha}$[/tex]

[tex]$v_{\alpha} = \sqrt{\frac{2 \Delta V q_{\alpha}}{m_{\alpha}}}$[/tex]

[tex]$v_{\alpha} = \sqrt{\frac{2(3.45 \times 10^{-3 })(3.2 \times 10^{-19})}{6.68 \times 10^{-27}}}$[/tex]

[tex]$v_{\alpha} \approx 575 \ m/s$[/tex]

The mechanical energy is conserved in the presence of the following conservative forces :

-- electrostatic forces

-- magnetic forces

-- gravitational forces

Answer:

2.5 m/s²

Explanation:

From the question

F = ma................... Equation 1

Where F = Tension, m = mass, a = acceleration of the car

make a the subject of the equation

a = F/m.................. Equation 2

Given: F = 1500 N, m = 600 kg

Substitute these values into equation 2

a = 1500/600

a = 2.5 m/s²

Hence the largest acceleration the rope can give to the car is 2.5 m/s²

Answer:

[tex]0.629\ \text{rad/s}^2[/tex] counterclockwise

[tex]9.98\ \text{s}[/tex]

Explanation:

[tex]r_1[/tex] = Small drive wheel radius = 2.2 cm

[tex]\alpha_1[/tex] = Angular acceleration of the small drive wheel = [tex]8\ \text{rad/s}^2[/tex]

[tex]r_2[/tex] = Radius of pottery wheel = 28 cm

[tex]\alpha_2[/tex] = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

[tex]r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2[/tex]

The angular acceleration of the pottery wheel is [tex]0.629\ \text{rad/s}^2[/tex].

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

[tex]\omega_i[/tex] = Initial angular velocity = 0

[tex]\omega_f[/tex] = Final angular velocity = [tex]60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}[/tex]

t = Time taken

From the kinematic equations of linear motion we have

[tex]\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}[/tex]

The time it takes the pottery wheel to reach the required speed is [tex]9.98\ \text{s}[/tex]

Answer:

2) twice the amplitude and half the wavelength

Explanation:

The diagram below represent that the waves A and B in the same medium should be option b where the amplitude is to be twice and the wavelength should be half.

What is amplitude?

Amplitude in terms of physics that represent the maximum displacement or the distance that should be moved via the point with respect to the vibrating body or the wave that should be determined from the equilibrium position.

Also, it should be equivalent to the one half the vibration path length.

Therefore, the option b is correct.

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Answer:

a = 6.25 m/s/s

d = 50 m

Explanation:

Given:

v1 (initial velocity)= 0 m/s (cz its at rest)

v2 (final velocity)= 25 m/s

t = 4s

a = ?

d = ?

to determine acceleration

a = (v2 - v1)/ t

= (25m/s - 0m/s)/4s

= 6.25 m/s/s

to determine distance traveled

d = 1/2(v1 + v2)t

=1/2(0m/s+25m/s)(4s)

=50 m

Answer:

Answer in explanation.

Explanation:

Using Equation

[tex]v = u + at[/tex]

where v is the final velocity

u is initial velocity

a is acceleration

t is time taken

given u = 0, v = 25, t = 4,

[tex]25 = 0 + 4a \\ 4a = 25 \\ a = 6.25 \frac{m}{ {s}^{2} } [/tex]

Now, using equation

[tex]v {}^{2} = {u}^{2} + 2as[/tex]

where v and u remains the same, a = 6.25 and s is the distance,

[tex](25) {}^{2} = \: {0}^{2} + 2(6.25)s \\ 12.5s = 625 \\ s = \frac{625}{12.5} \\ s = 50m[/tex]

a centrifugal clutch works, as the name suggests, through centrifugal force. ... The rotation of the hub forces the shoes or flyweights outwards until they come into contact with the clutch drum, the friction material transmits the torque from the flyweights to the drum. The drive is then connected

[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]

We have ―

Initial velocity, u = 18 m/sFinal velocity, v = 30 m/sTime taken, t = 3 seconds

We've been asked to calculate acceleration.

[tex]\qquad \implies\boxed{\red{\sf{ a = \dfrac{v-u}{t} }}}\\[/tex]

a denotes accelerationv denotes final velocityu denotes initial velocityt denotes time

[tex] \twoheadrightarrow \quad \sf {a = \dfrac{30-18}{3} \; ms^{-2} } \\ [/tex]

[tex] \twoheadrightarrow \quad \sf {a =\cancel{ \dfrac{12}{3} \; ms^{-2} }} \\ [/tex]

[tex]\twoheadrightarrow \quad \boxed{\red{\sf{ a = 4 \; ms^{-2} }}}\\[/tex]

Therefore, acceleration of the car is 4 m/s².

Answer:

2. - B.

3. - True.

4. - B.

5. - D.

Explanation:

2. To find the speed in feet per minute, you need to divide the time by time and divide the feet by the time

2/2 = 1 minute

100/2 = 50 feet

3. 45 N - 20 N = 15 N

So the difference between the forces is 15 N

4. As just about everyone knows, when something falls, that is because of gravity. Gravity is the force that pulls everything.

5. Inertia is when an object stays unchanged. So if something stays in motion or does not stop, it has not changed

Answer:962 hz

Explanation: got it right on acellus

The frequency of the siren when the cyclist is stationary will be 963 Hz.

What is frequency ?

The frequency of a wave is the number of cycles per second.

FRom the doppler effect,

f =f'[ (V+Vs/V-Vo) ]

Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s

Substitute the value into the expression , we get

f = 894 x [(343/343 - 24.5)}

f = 963 Hz

Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.

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Answer:

45,86N

Explanation:

Fk=Uk×N

=0,78×6×9.8

=45,86N

Answer:

1) Because of the size and time the sound wave moves, an echo is typically transparent and easy to discern. Since reverberations typically don't have enough distance or time to fly, they will pile up on top of each other, making it impossible to understand.

People will detect an echo if the distance between the source of the sound and the reflected body is greater than 50 feet. When a sound wave is bounced off a nearby surface, it may create a reverberation.

2) The speed of sound in hot air is more than that in cold air because air molecules are traveling faster in hot air.

Explanation: